If ( a / 2 ) = ( b / 3 ) = ( c / 4 ) = ( 2a – 3b + 4c ) / ( p ), then find p.

Given : ( a / 2 ) = ( b / 3 ) = ( c / 4 ) = ( 2a – 3b + 4c ) / ( p ) = k ( Say ) .

∴ a = 2k

b = 3k

c = 4k

and 2a – 3b + 4c = pk

⇒ 2 ( 2k ) – 3 ( 3k ) + 4 ( 4k ) = pk

⇒ 4k – 9k + 16k = pk

⇒ 11k = pk

⇒ 11 = p

∴ p = 11

## 0 Comments