xy2and y = 2a when x = a, then show that y2 = 4ax .

Solution : xy2

x = ky2 ——————-( 1 )

where k is variation constant .

when x = a and y 2a, then from equation ( 1 ),

a = k ( 2a )2

⇒ a = k × 4a2

⇒ 1 = k ( 4a )

⇒ k = 1 / ( 4a )

putting the value of k = 1 / ( 4a ) in equation ( 1 ), we get,

x = ky2

x = { 1 / ( 4a ) } y2

y2 = 4ax ( showed )


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