Class 10 Maths Tutorials
sin 30º + sin 60º > sin 90º ( WBBSE – 2019 )
Write true or false : sin 30º + sin 60º > sin 90º Answer : True Explanation : LHS = sin 30º + sin 60º = 1/2 +√3/2 = 1 + √3/2 = 1 + 1.732/2 = 2.732/2 = 1.366 Read more…
Write true or false : sin 30º + sin 60º > sin 90º Answer : True Explanation : LHS = sin 30º + sin 60º = 1/2 +√3/2 = 1 + √3/2 = 1 + 1.732/2 = 2.732/2 = 1.366 Read more…
The variable x1, x2,x3, ………….,x100 are in ascending order of their magnitude, then the median of the variable is ______. Answer: ( x50+x51 )/2 Explanation: Number of variables (x) = 100 ∴ Median = 1/2 [ (x/2)th+(x/2+1)th ] =1/2 [ Read more…
The mean of the data x1, x2, x3, …………… x10 is 20 then the mean of (x1 + 4) , (x2 + 4) , (x3 + 4) , …….(x10 + 4) will be a) 20 b) 24 c) 40 d) Read more…
Write true or false : Only one circle can be drawn through three non-collinear points. Answer : True Explanatation : Through 3 non-collnear points, only one triangle can be drawn. Hence, only one circumcircle can be drawn. Therefore, the given Read more…
If the bases of two triangles are situated on same line and other vertex of the two triangles are common, then the ratio of the areas of two triangles ______to the ratio of their bases. Answer: equal Explanation: Area of Read more…
The simplest value of cos53˚/sin37˚is ______. Answer: 1 Explanation: cos53˚/sin37˚= cos(90-37)/ sin37˚ [ ∵ 53+37=90 ⇒ 53 = 90-37 ] = sin37˚/sin37˚ [ ∵ cos(90-θ) = sinθ ] = 1
Number of surfaces of a solid right circular cylinder is _______. Answer : 03 Explaination :
Introduction : In our dailylife, we may observe that the path of the rays of light have been bent when the these go from one medium to another medium at the separation of the two media. A man sees a Read more…
O is te centre of a circle and AB a diameter ABCD is a cyclic quadrilateral. ∠ABC=65°, ∠DAC=40°, then the measure of ∠BCD is ______. a)75° b)105° c)115° d)80° Answer : 115° Explaination: Given: ∠ABC=65° ∠DAC=40° ∠BCD= ?? ∵ ∠ACB Read more…
If tan∝ + cot∝ = 2, then the value of tan13∝ + cot13∝ is ______. a) 13 b) 2 c) 1 d) 0 Answer : b ) 2 Explaination : Given : tan∝ + cot∝ = 2 ⇒ tan∝ + 1/tan∝=2 Read more…